单选题Exhibit: Examine the data in the EMPLOYEES table. Examine the subquery: SELECT last_name FROM employees WHERE salary IN (SELECT MAX(salary) FROM employees GROUP BY department_id); Which statement is true?()AThe SELECT statement is syntactically accura

题目
单选题
Exhibit: Examine the data in the EMPLOYEES table. Examine the subquery: SELECT last_name FROM employees WHERE salary IN (SELECT MAX(salary) FROM employees GROUP BY department_id); Which statement is true?()
A

The SELECT statement is syntactically accurate.

B

The SELECT statement does not work because there is no HAVING clause.

C

The SELECT statement does not work because the column specified in the GROUP BY clause is not in the SELECT list.

D

The SELECT statement does not work because the GROUP BY clause should be in the main query and not in the subquery.


相似考题
参考答案和解析
正确答案: C
解析: 暂无解析
更多“单选题Exhibit: Examine the data in the EMPLOYEES table. Examine the subquery: SELECT last_name FROM employees WHERE salary IN (SELECT MAX(salary) FROM employees GROUP BY department_id); Which statement is true?()A The SELECT statement is syntactically accu”相关问题
  • 第1题:

    Examine the data in the EMPLOYEES table:LAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000...Which three subqueries work? ()

    A. SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);

    B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    C. SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    D. SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    E. SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);

    F. SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));


    参考答案:C, D, E

  • 第2题:

    Click the Exhibit button and examine the data in the EMPLOYEES table.Examine the subquery:SELECT last_nameFROM employeesWHERE salary IN (SELECT MAX(salary)FROM employeesGROUP BY department_id);Which statement is true?()

    A.The SELECT statement is syntactically accurate.

    B.The SELECT statement does not work because there is no HAVING clause.

    C.The SELECT statement does not work because the column specified in the GROUP BY clause is not in the SELECT list.

    D.The SELECT statement does not work because the GROUP BY clause should be in the main query and not in the subquery.


    参考答案:A

  • 第3题:

    The EMPLOYEE tables has these columns: LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) COMMISSION_PCT NUMBER(5,2) You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column. Which SQL statement displays the desired results?()

    • A、SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;
    • B、SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;
    • C、SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;
    • D、SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

    正确答案:D

  • 第4题:

    Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) JOB_CAT VARCHAR2(30) SALARY NUMBER(8,2) Which statement shows the department ID, minimum salary, and maximum salary paid in that department, only of the minimum salary is less then 5000 and the maximum salary is more than 15000?()

    • A、SELECT dept_id, MIN(salary(, MAX(salary) FROM employees WHERE MIN(salary) <5000 AND MAX (salary) > 15000;
    • B、SELECT dept_id, MIN(salary), MAX(salary) FROM employees WHERE MIN(salary) < 5000 AND MAX(salary) > 15000 GROUP BY dept_id;
    • C、SELECT dept_id, MIN(salary), MAX(salary) FROM employees HAVING MIN(salary) <5000 AND MAX (salary) > 15000;
    • D、SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id HAVING MIN (salary) < 5000 AND MAX(salary)
    • E、SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id, salary HAVING MIN (salary) <5000 AND MAX (salary) > 15000;

    正确答案:D

  • 第5题:

    Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER SALARY NUMBER What is the correct syntax for an inline view? ()

    • A、SELECT a.last_name, a.salary, a.department_id, b.maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary < b.maxsal;
    • B、SELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))
    • C、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);
    • D、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);

    正确答案:A

  • 第6题:

    Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data type Remarks EMPLOYEE_ID NUMBER NOT NULL, Primary Key EMP_NAME VARCHAR2 (30) JOB_ID VARCHAR2 (20) SALARY NUMBER MGR_ID NUMBER References EMPLOYEE_ID COLUMN DEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS table DEPARTMENTSColumn name Data type Remarks DEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30) MGR_ID NUMBER References MGR_ID column of the EMPLOYEES table Evaluate this SQL statement: SELECT employee_id, e.department_id, department_name, salary FROM employees e, departments d WHERE e. department_id = d.department_id; Which SQL statement is equivalent to the above SQL statement?()

    • A、SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);
    • B、SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;
    • C、SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;
    • D、SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);

    正确答案:C

  • 第7题:

    Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) JOB_CAT VARCHARD2(30) SALARY NUMBER(8,2) Which statement shows the maximum salary paid in each job category of each department?()

    • A、SELECT dept_id, job_cat, MAX(salary) FROM employees WHERE salary > MAX (salary);
    • B、SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept_id,job_cat;
    • C、SELECT dept_id, job_cat, MAX(salary) FROM employees;
    • D、SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept_id;
    • E、SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept _ id job _ cat salary;

    正确答案:B

  • 第8题:

    Examine the structure of the EMP_DEPT_VU view: Column Name Type Remarks EMPLOYEE_ID NUMBER From the EMPLOYEES table EMP_NAME VARCHAR2(30) From the EMPLOYEES table JOB_ID VARCHAR2(20) From the EMPLOYEES table SALARY NUMBER From the EMPLOYEES table DEPARTMENT_ID NUMBER From the DEPARTMENTS table DEPT_NAME VARCHAR2(30) From the DEPARTMENTS table Which SQL statement produces an error?()

    • A、SELECT * FROM emp_dept_vu;
    • B、SELECT department_id, SUM(salary) FROM emp_dept_vu GROUP BY department _ id;
    • C、SELECT department_id, job_id, AVG(salary) FROM emp_dept_vu GROUP BY department _ id, job_id;
    • D、SELECT job_id, SUM(salary) FROM emp_dept_vu WHERE department_id IN (10,20) GROUP BY job_id HAVING SUM (salary) > 20000
    • E、None of the statements produce an error; all are valid.

    正确答案:E

  • 第9题:

    单选题
    Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER SALARY NUMBER What is the correct syntax for an inline view?()
    A

    SELECT a.last_name, a.salary, a.department_id,

    B

    maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary < b.maxsal;

    C

    SELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))

    D

    SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);

    E

    SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);


    正确答案: C
    解析: 暂无解析

  • 第10题:

    单选题
    Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE NEW_EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2 (60) Which DELETE statement is valid?()
    A

    DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);

    B

    DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_ employees);

    C

    DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = 'carrey');

    D

    DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = 'carrey');


    正确答案: C
    解析: 暂无解析

  • 第11题:

    多选题
    Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?()
    A

    SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);

    B

    SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);

    C

    SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);

    D

    SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);

    E

    SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);

    F

    SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));


    正确答案: E,C
    解析: 暂无解析

  • 第12题:

    多选题
    Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? ()
    A

    SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);

    B

    SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    C

    SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    D

    SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    E

    SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);

    F

    SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));


    正确答案: D,B
    解析: 暂无解析

  • 第13题:

    Click the Exhibit button and examine the data in the EMPLOYEES table.Which three subqueries work? ()

    A.SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);

    B.SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);

    C.SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);

    D.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);

    E.SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);

    F.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));


    参考答案:C, D, E

  • 第14题:

    下面哪条语句可以取出薪水最高的前三个人:()

    • A、SELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY );
    • B、SELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY ) WHERE ROWNUM<=3;
    • C、SELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY DESC) WHERE ROWNUM<=3;
    • D、SELECT * FROM EMPLOYEES WHERE ROWNUM<=3 ORDER BY SALARY DESC;

    正确答案:C

  • 第15题:

    Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data type Remarks EMPLOYEE_ID NUMBER NOT NULL, Primary Key EMP_NAME VARCHAR2 (30) JOB_ID VARCHAR2 (20) SALARY NUMBER MGR_ID NUMBER References EMPLOYEE_ID COLUMN DEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS table DEPARTMENTSColumn name Data type Remarks DEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30) MGR_ID NUMBER References MGR_ID column of the EMPLOYEES table Evaluate this SQL statement: SELECT employee_id, e.department_id, department_name, salary FROM employees e, departments d WHERE e. department_id = d.department_id; Which SQL statement is equivalent to the above SQL statement? ()

    • A、SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);
    • B、SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;
    • C、SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;
    • D、SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);

    正确答案:C

  • 第16题:

    Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) Which statement produces the number of different departments that have employees with last name Smith?()

    • A、SELECT COUNT(*) FROM employees WHERE last_name='Smith';
    • B、SELECT COUNT(dept_id) FROM employees WHERE last_name='Smith';
    • C、SELECT DISTINCT(COUNT(dept_id)) FROM employees WHERE last_name='Smith';
    • D、SELECT COUNT(DISTINCT dept_id) FROM employees WHERE last_name='Smith';
    • E、SELECT UNIQUE(dept_id) FROM employees WHERE last_name='Smith';

    正确答案:D

  • 第17题:

    Which SQL statement generates the alias Annual Salary for the calculated column SALARY*12?()

    • A、SELECT ename, salary*12 'Annual Salary' FROM employees;
    • B、SELECT ename, salary*12 "Annual Salary" FROM employees;
    • C、SELECT ename, salary*12 AS Annual Salary FROM employees;
    • D、SELECT ename, salary*12 AS INITCAP("ANNUAL SALARY") FROM employees

    正确答案:B

  • 第18题:

    Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?()

    • A、SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);
    • B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);
    • C、SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);
    • D、SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);
    • E、SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);
    • F、SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

    正确答案:C,D,E

  • 第19题:

    Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? ()

    • A、SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);
    • B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);
    • C、SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);
    • D、SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);
    • E、SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);
    • F、SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

    正确答案:C,D,E

  • 第20题:

    Examine the structure of the EMP_DEPT_VU view: Column Name Type Remarks EMPLOYEE_ID NUMBER From the EMPLOYEES table EMP_NAME VARCHAR2(30) From the EMPLOYEES table JOB_ID VARCHAR2(20) From the EMPLOYEES table SALARY NUMBER From the EMPLOYEES table DEPARTMENT_ID NUMBER From the DEPARTMENTS table DEPT_NAME VARCHAR2(30) From the DEPARTMENTS table Which SQL statement produces an error?()

    • A、SELECT * FROM emp_dept_vu;
    • B、SELECT department_id, SUM(salary) FROM emp_dept_vu GROUP BY department _ id;
    • C、SELECT department_id, job_id, AVG(salary) FROM emp_dept_vu GROUP BY department _ id, job_id;
    • D、SELECT job_id, SUM(salary) FROM emp_dept_vu WHERE department_id IN (10,20) GROUP BY job_id HAVING SUM (salary) > 20000
    • E、None of the statements produce an error; all are valid.

    正确答案:E

  • 第21题:

    单选题
    Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_ NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) JOB_CAT VARCHAR2(30) SALARY NUMBER(8,2) Which statement shows the department ID, minimum salary, and maximum salary paid in that department, only if the minimum salary is less than 5000 and maximum salary is more than 15000?()
    A

    SELECT dept_id, MIN(salary), MAX(salary) FROM employees WHERE MIN(salary) < 5000 AND MAX(salary) > 15000;

    B

    SELECT dept_id, MIN(salary), MAX(salary) FROM employees WHERE MIN(salary) < 5000 AND MAX(salary) > 15000 GROUP BY dept_id;

    C

    SELECT dept_id, MIN(salary), MAX(salary) FROM employees HAVING MIN(salary) < 5000 AND MAX(salary) > 15000;

    D

    SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id HAVING MIN(salary) < 5000 AND MAX(salary) > 15000;

    E

    SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id, salary HAVING MIN(salary) < 5000 AND MAX(salary) > 15000;


    正确答案: E
    解析: 暂无解析

  • 第22题:

    多选题
    Examine the data in the EMPLOYEES table: Which three subqueries work? ()
    A

    SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);

    B

    SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    C

    SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    D

    SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    E

    SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);

    F

    SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));


    正确答案: D,E
    解析: 暂无解析

  • 第23题:

    单选题
    Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE NEW_EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2(60) Which DELETE statement is valid?()
    A

    DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);

    B

    DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_employees);

    C

    DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name ='Carrey');

    D

    DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE last_name ='Carrey');


    正确答案: B
    解析: 暂无解析